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@@ -12,6 +12,11 @@
</ul>
<li><a href="#adding">Adding an applet to busybox</a></li>
<li><a href="#standards">What standards does busybox adhere to?</a></li>
+ <li><a href="#tips">Tips and tricks.</a></li>
+ <ul>
+ <li><a href="#tips_encrypted_passwords">Encrypted Passwords</a></li>
+ <li><a href="#tips_vfork">Fork and vfork</a></li>
+ </ul>
</ul>
<h2><b><a name="goals" />What are the goals of busybox?</b></h2>
@@ -172,6 +177,116 @@ applet is otherwise finished. When polishing and testing a busybox applet,
we ensure we have at least the option of full standards compliance, or else
document where we (intentionally) fall short.</p>
+<h2><a name="tips" />Programming tips and tricks.</a></h2>
+
+<p>Various things busybox uses that aren't particularly well documented
+elsewhere.</p>
+
+<h2><a name="tips_encrypted_passwords">Encrypted Passwords</a></h2>
+
+<p>Password fields in /etc/passwd and /etc/shadow are in a special format.
+If the first character isn't '$', then it's an old DES style password. If
+the first character is '$' then the password is actually three fields
+separated by '$' characters:</p>
+<pre>
+ <b>$type$salt$encrypted_password</b>
+</pre>
+
+<p>The "type" indicates which encryption algorithm to use: 1 for MD5 and 2 for SHA1.</p>
+
+<p>The "salt" is a bunch of ramdom characters (generally 8) the encryption
+algorithm uses to perturb the password in a known and reproducible way (such
+as by appending the random data to the unencrypted password, or combining
+them with exclusive or). Salt is randomly generated when setting a password,
+and then the same salt value is re-used when checking the password. (Salt is
+thus stored unencrypted.)</p>
+
+<p>The advantage of using salt is that the same cleartext password encrypted
+with a different salt value produces a different encrypted value.
+If each encrypted password uses a different salt value, an attacker is forced
+to do the cryptographic math all over again for each password they want to
+check. Without salt, they could simply produce a big dictionary of commonly
+used passwords ahead of time, and look up each password in a stolen password
+file to see if it's a known value. (Even if there are billions of possible
+passwords in the dictionary, checking each one is just a binary search against
+a file only a few gigabytes long.) With salt they can't even tell if two
+different users share the same password without guessing what that password
+is and decrypting it. They also can't precompute the attack dictionary for
+a specific password until they know what the salt value is.</p>
+
+<p>The third field is the encrypted password (plus the salt). For md5 this
+is 22 bytes.</p>
+
+<p>The busybox function to handle all this is pw_encrypt(clear, salt) in
+"libbb/pw_encrypt.c". The first argument is the clear text password to be
+encrypted, and the second is a string in "$type$salt$password" format, from
+which the "type" and "salt" fields will be extracted to produce an encrypted
+value. (Only the first two fields are needed, the third $ is equivalent to
+the end of the string.) The return value is an encrypted password in
+/etc/passwd format, with all three $ separated fields. It's stored in
+a static buffer, 128 bytes long.</p>
+
+<p>So when checking an existing password, if pw_encrypt(text,
+old_encrypted_password) returns a string that compares identical to
+old_encrypted_password, you've got the right password. When setting a new
+password, generate a random 8 character salt string, put it in the right
+format with sprintf(buffer, "$%c$%s", type, salt), and feed buffer as the
+second argument to pw_encrypt(text,buffer).</p>
+
+<h2><a name="tips_vfork">Fork and vfork</a></h2>
+
+<p>On systems that haven't got a Memory Management Unit, fork() is unreasonably
+expensive to implement, so a less capable function called vfork() is used
+instead.</p>
+
+<p>The reason vfork() exists is that if you haven't got an MMU then you can't
+simply set up a second set of page tables and share the physical memory via
+copy-on-write, which is what fork() normally does. This means that actually
+forking has to copy all the parent's memory (which could easily be tens of
+megabytes). And you have to do this even though that memory gets freed again
+as soon as the exec happens, so it's probably all a big waste of time.</p>
+
+<p>This is not only slow and a waste of space, it also causes totally
+unnecessary memory usage spikes based on how big the _parent_ process is (not
+the child), and these spikes are quite likely to trigger an out of memory
+condition on small systems (which is where nommu is common anyway). So
+although you _can_ emulate a real fork on a nommu system, you really don't
+want to.</p>
+
+<p>In theory, vfork() is just a fork() that writeably shares the heap and stack
+rather than copying it (so what one process writes the other one sees). In
+practice, vfork() has to suspend the parent process until the child does exec,
+at which point the parent wakes up and resumes by returning from the call to
+vfork(). All modern kernel/libc combinations implement vfork() to put the
+parent to sleep until the child does its exec. There's just no other way to
+make it work: they're sharing the same stack, so if either one returns from its
+function it stomps on the callstack so that when the other process returns,
+hilarity ensues. In fact without suspending the parent there's no way to even
+store separate copies of the return value (the pid) from the vfork() call
+itself: both assignments write into the same memory location.</p>
+
+<p>One way to understand (and in fact implement) vfork() is this: imagine
+the parent does a setjmp and then continues on (pretending to be the child)
+until the exec() comes around, then the _exec_ does the actual fork, and the
+parent does a longjmp back to the original vfork call and continues on from
+there. (It thus becomes obvious why the child can't return, or modify
+local variables it doesn't want the parent to see changed when it resumes.)
+
+<p>Note a common mistake: the need for vfork doesn't mean you can't have two
+processes running at the same time. It means you can't have two processes
+sharing the same memory without stomping all over each other. As soon as
+the child calls exec(), the parent resumes.</p>
+
+<p>(Now in theory, a nommu system could just copy the _stack_ when it forks
+(which presumably is much shorter than the heap), and leave the heap shared.
+In practice, you've just wound up in a multi-threaded situation and you can't
+do a malloc() or free() on your heap without freeing the other process's memory
+(and if you don't have the proper locking for being threaded, corrupting the
+heap if both of you try to do it at the same time and wind up stomping on
+each other while traversing the free memory lists). The thing about vfork is
+that it's a big red flag warning "there be dragons here" rather than
+something subtle and thus even more dangerous.)</p>
+
<br>
<br>
<br>